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FWIWFor what it is worth, both $Q^{\alpha}$ and $F$ are objects that need to exist before we can apply Noether's theorem, i.e. they are assumptions. $Q^{\alpha}$ is the assumed infinitesimal transformation of the variable $q^{\alpha}$, while the total time-derivative of $F$ is assumed to be the infinitesimal change of the Lagrangian under said infinitesimal transformation, cf. eq. (7.2).

FWIW, both $Q^{\alpha}$ and $F$ are objects that need to exist before we can apply Noether's theorem, i.e. they are assumptions. $Q^{\alpha}$ is the assumed infinitesimal transformation of the variable $q^{\alpha}$, while the total time-derivative of $F$ is assumed to be the infinitesimal change of the Lagrangian under said infinitesimal transformation, cf. eq. (7.2).

For what it is worth, both $Q^{\alpha}$ and $F$ are objects that need to exist before we can apply Noether's theorem, i.e. they are assumptions. $Q^{\alpha}$ is the assumed infinitesimal transformation of the variable $q^{\alpha}$, while the total time-derivative of $F$ is assumed to be the infinitesimal change of the Lagrangian under said infinitesimal transformation, cf. eq. (7.2).

Source Link
Qmechanic
  • 213.1k
  • 48
  • 590
  • 2.3k

FWIW, both $Q^{\alpha}$ and $F$ are objects that need to exist before we can apply Noether's theorem, i.e. they are assumptions. $Q^{\alpha}$ is the assumed infinitesimal transformation of the variable $q^{\alpha}$, while the total time-derivative of $F$ is assumed to be the infinitesimal change of the Lagrangian under said infinitesimal transformation, cf. eq. (7.2).