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Dec 19, 2022 at 1:54 comment added Lucas Baldo I would also add that the excitation spectrum $\epsilon_n= E_n - E_0$ is also independent of $\alpha$.
Apr 29, 2020 at 13:07 review Late answers
Apr 29, 2020 at 13:30
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Apr 29, 2020 at 12:53
Apr 29, 2020 at 12:46 history answered PPIP CC BY-SA 4.0