Timeline for Legendre transform of $S(E,V)$ to obtain $F(T,V)$
Current License: CC BY-SA 4.0
4 events
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Apr 28, 2023 at 6:20 | comment | added | naturallyInconsistent | Legendre transforms of S are Massieu functions, and they are quite similar to the usual potentials. Precisely because they are so similar, people have not bothered to work too hard in terms of them. After all, you get similar physics. I mean, studying $F = E - TS$ will get a similar result as studying $-F/T = S - E/T$ | |
Apr 29, 2020 at 8:36 | comment | added | Karel Peetermans | @RoshanShrestha Then I would suggest looking at this post. You cannot directly go from S to F, only by inverting it to E first. As you tried it, you are creating a new variable which is the Legendre transform of entropy but (I think) it is not really related to F directly. Only in the sense that $-T\cdot(S-\frac{E}{T}) = E - TS = F$. | |
Apr 29, 2020 at 8:33 | comment | added | Roshan Shrestha | Yeah, I know that F is a Legendre transform of and E and can derive from E, but why can't we use it for S as well and derive $F(T,V)$ from $S(E,V)$? | |
Apr 29, 2020 at 8:30 | history | answered | Karel Peetermans | CC BY-SA 4.0 |