Timeline for How to calculate the fraction of light rays reflected?
Current License: CC BY-SA 4.0
8 events
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Apr 13, 2020 at 15:15 | comment | added | boyfarrell | Yes! I that’s correct. A solid angle defines a “volume” of directions from a starting point. The first integral in actually over $\theta$, it sweeps out a “standard” angle (it looks like a “plane” of directions from $\theta_c$ to $\pi/2$). The second integral, over $\phi$, rotates the “plane” to define a “volume” of angles: a solid angle. Yes a solid angle is defined by a two angular ranges: one over $\theta$ the other over $\phi$. | |
Apr 13, 2020 at 15:03 | comment | added | Mathrix | Thank you! I don't know if I was clear so I am asking again: By making the second integral's boundaries $\frac{\pi}{2}$ to $\theta_c$ we kind of calculated the area in two dimensions. And by making the first integral's boundaries $2\pi$ to $0$, we integrated the value (I don't really know what it is :/) over the second angle of the solid angle. I am sorry this is not my first language but what I want to say at short is that solid angle has two angles and that's why we integrate it twice. Is that it? | |
Apr 13, 2020 at 14:54 | comment | added | boyfarrell | These are not length integrals they are direction (solid angle) integrals. Imagine the integral is sweeping out a “volume”, if you use the limits above it sweeps out the yellow section in the diagram. This is what I was trying to show with that. | |
Apr 13, 2020 at 14:50 | comment | added | Mathrix | I think I understand why you put these limits but could you please explain why did you choose these ones? Especially for the first integral. Is it because it's a hemisphere with a radius of $\frac{thickness\space of\space the\space liquid\space layer}{2}\space \space \space$? | |
Apr 10, 2020 at 8:16 | history | edited | boyfarrell | CC BY-SA 4.0 |
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Apr 9, 2020 at 22:52 | vote | accept | Mathrix | ||
Apr 9, 2020 at 17:17 | history | edited | boyfarrell | CC BY-SA 4.0 |
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Apr 9, 2020 at 12:25 | history | answered | boyfarrell | CC BY-SA 4.0 |