Timeline for Can multiple electron pairs be present in a single orbital?
Current License: CC BY-SA 4.0
6 events
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| Apr 8, 2020 at 13:15 | comment | added | Souparna Nath | O okay I see. Probably my concept of treating 2 electron combination as like a single spin 1 particle (like a photon for example) is wrong in all cases. Thank You. | |
| Apr 7, 2020 at 7:25 | history | edited | taciteloquence | CC BY-SA 4.0 |
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| Apr 6, 2020 at 10:26 | comment | added | taciteloquence | You would have to be able to antisymmetrize the whole multi-electron wavefucntion $\psi( \vec r_1, \vec r_2, \vec r_3, \vec r_4) $ with respect to the exchange of any two $r_i$, $r_j$. | |
| Apr 6, 2020 at 10:24 | comment | added | taciteloquence | Is the same thing. The electron pair isn't a tightly-bound state of two electrons they aren't bound at all, so you can't treat these two pairs of electrons as two bosons. | |
| Apr 4, 2020 at 17:20 | comment | added | Souparna Nath | No you see, I am talking of two electron "pairs", i.e., two (e↑e↓) pairs. Each of this (e↑e↓) pair is a boson right (having a total spin of 1 (triplet) or 0 (singlet)) ? Both these spins spates are integer. Now when you bring 2 electron pairs, both of these pairs "individually" have integer spins. So, they can combine to form a symmetric spin state (say of total spin 2 which is a symmetric state) which means they can stay in the same state (which I claimed to be Hydrogen 1s orbital just because its a symmetric SPATIAL wavefunction). | |
| Apr 4, 2020 at 4:11 | history | answered | taciteloquence | CC BY-SA 4.0 |