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Apr 4, 2020 at 22:09 comment added SRS The question is whether SSB implies charge nonconservation (yes or no) and whether FP theorem is the correct way to address/understand this. I don't see what is the confusion. @ACuriousMind
Apr 4, 2020 at 22:04 history edited ACuriousMind CC BY-SA 4.0
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Apr 4, 2020 at 22:01 history edited SRS CC BY-SA 4.0
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Apr 4, 2020 at 21:58 comment added SRS Yes. It is a constant. physics.stackexchange.com/q/228494 see here the expression in David Bar Moshe's answer. @ACuriousMind
Apr 4, 2020 at 21:51 comment added ACuriousMind You didn't really fix the typo fqq pointed out - the integrand of your r.h.s. is - as written - a constant, not a function of $x$ you could meaningfully integrate over all of space. It is still not clear to me what exactly you want to know here. Your Q1 seems to be nitpicking other people's language rather than asking a question about physics, and your Q2 seems similarily a play on words: What is the relevant difference between the two options you offer there?
Apr 3, 2020 at 17:24 history edited SRS CC BY-SA 4.0
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Apr 3, 2020 at 17:24 comment added SRS Thanks. The comma is a typo. Translational invariance of the vacuum is used to eliminate the x dependence of $j_0$.
Apr 3, 2020 at 17:22 comment added fqq It does not. I didn't post an answer, but a comment pointing out that there is something wrong with the expression, I guess it should be $j_0(x)Q$, and is the comma supposed to be there?
Apr 3, 2020 at 17:18 comment added SRS @fqq ?? How does that answer my questions? In particular, question 2?
Apr 3, 2020 at 17:15 comment added fqq As written, the integrand is not a function of $\bf{x}$.
Apr 3, 2020 at 16:40 history edited SRS CC BY-SA 4.0
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Apr 3, 2020 at 16:27 history edited SRS CC BY-SA 4.0
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Apr 3, 2020 at 16:22 history edited SRS CC BY-SA 4.0
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Apr 3, 2020 at 16:22 answer added mike stone timeline score: 1
Apr 3, 2020 at 16:18 comment added ACuriousMind See physics.stackexchange.com/q/228494/50583
Apr 3, 2020 at 15:41 history asked SRS CC BY-SA 4.0