Timeline for I do not understand this bra-ket notation equality for BCFW recursion
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Apr 8, 2020 at 14:10 | comment | added | Akoben | I've updated the answer. Momentum conservation just tells you how to shift the other particle (so that they cancel in momentum conservation, as you correctly pointed out) and $\hat{p}_i^2 = 0$ just tells you what $q$ has to be. | |
| Apr 8, 2020 at 14:08 | history | edited | Akoben | CC BY-SA 4.0 |
edited to expand answer a bit.
|
| Apr 7, 2020 at 13:30 | comment | added | user256673 | The expansion makes perfect sense to me, but I don't understand how q was chosen based on the momentum conservation rules, because if that was the case wouldn't it be that: $$\sum p_i = \sum \hat{p}_i = p_1 + p_2 = \hat{p}_1 + \hat{p}_2 $$ but then because the value of $zq$ changes sign in the equations: $$\hat{p_1}=p_1 -zq \hspace{5mm}; \hspace{5mm} \hat{p_n} = p_n +zq$$ don't they cancel out? And I don't understand how $(\hat{p}_i^2 = 0)$ helps either. I know this is based on $p_1 = |1\rangle|1]$ but could you help me understand the value of q? | |
| Mar 28, 2020 at 11:57 | vote | accept | user7077252 | ||
| Mar 28, 2020 at 11:56 | vote | accept | user7077252 | ||
| Mar 28, 2020 at 11:57 | |||||
| Mar 28, 2020 at 7:57 | history | answered | Akoben | CC BY-SA 4.0 |