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How to finddraw the velocityelectric field line in the constrained motiontwo positive charged system?

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Qmechanic
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how How to find the velocity in the constrainconstrained motion?

What I am taught is that electric field is the direction in which force is experienced by the positive charge particle and the amount of force is determined by the density of the electric field. If two positive charge are kept d distance apart then how will the electric field line behave which emerges from the point O and P on the charge particles?   

enter image description here what

what I think is that if we place a positive test charged particle near O(initial velocity=0) then test particle will experience a force pushing it away from the charge particle and finally the particle will reach the equilibrium point where there will no force. the field line must be the line tangent to all the force vectors which acted upon the test particle. No where the direction of the force acting on the particle is changed that means the force line must be straight emerging from the charge particle and since at the equilibrium point there must be no force hence no field line. In every textbook the field line is curved upwards but is is clear that no where the test charge had experience a force with upward component. So how will the force line will proceed?

how to find the velocity in the constrain motion

What I am taught is that electric field is the direction in which force is experienced by the positive charge particle and the amount of force is determined by the density of the electric field. If two positive charge are kept d distance apart then how will the electric field line behave which emerges from the point O and P on the charge particles?  enter image description here what I think is that if we place a positive test charged particle near O(initial velocity=0) then test particle will experience a force pushing it away from the charge particle and finally the particle will reach the equilibrium point where there will no force. the field line must be the line tangent to all the force vectors which acted upon the test particle. No where the direction of the force acting on the particle is changed that means the force line must be straight emerging from the charge particle and since at the equilibrium point there must be no force hence no field line. In every textbook the field line is curved upwards but is is clear that no where the test charge had experience a force with upward component. So how will the force line will proceed?

How to find the velocity in the constrained motion?

What I am taught is that electric field is the direction in which force is experienced by the positive charge particle and the amount of force is determined by the density of the electric field. If two positive charge are kept d distance apart then how will the electric field line behave which emerges from the point O and P on the charge particles? 

enter image description here

what I think is that if we place a positive test charged particle near O(initial velocity=0) then test particle will experience a force pushing it away from the charge particle and finally the particle will reach the equilibrium point where there will no force. the field line must be the line tangent to all the force vectors which acted upon the test particle. No where the direction of the force acting on the particle is changed that means the force line must be straight emerging from the charge particle and since at the equilibrium point there must be no force hence no field line. In every textbook the field line is curved upwards but is is clear that no where the test charge had experience a force with upward component. So how will the force line will proceed?

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how to find the velocity in the constrain motion

What I am taught is that electric field is the direction in which force is experienced by the positive charge particle and the amount of force is determined by the density of the electric field. If two positive charge are kept d distance apart then how will the electric field line behave which emerges from the point O and P on the charge particles? enter image description here what I think is that if we place a positive test charged particle near O(initial velocity=0) then test particle will experience a force pushing it away from the charge particle and finally the particle will reach the equilibrium point where there will no force. the field line must be the line tangent to all the force vectors which acted upon the test particle. No where the direction of the force acting on the particle is changed that means the force line must be straight emerging from the charge particle and since at the equilibrium point there must be no force hence no field line. In every textbook the field line is curved upwards but is is clear that no where the test charge had experience a force with upward component. So how will the force line will proceed?