Skip to main content
7 events
when toggle format what by license comment
Apr 10, 2023 at 20:58 comment added Bruno Le Floch @Everiana Geodesics are well-defined with just an affine connection: math.stackexchange.com/questions/3729415 OTOH, computing the Kretschmann scalar requires contracting indices of the Riemann tensor in a way that requires a metric.
Mar 11, 2020 at 16:42 history edited Qmechanic CC BY-SA 4.0
edited tags
Mar 11, 2020 at 13:47 answer added Slereah timeline score: 3
Mar 9, 2020 at 15:18 answer added Void timeline score: 2
Mar 9, 2020 at 15:14 comment added KayS @Everiana Thanks for the comment. My question is about the singularities of a given metric, and if my understanding is correct, singularities of a metric are 'defined' by geodesic (in-)completeness. Therefore, it is more than natural to consider the Levi-Civita connection and the curvature computed by it. It is obvious that singularities and curvature are some-what related. My confusion is 'to what extent?'
Mar 9, 2020 at 14:48 comment added Evangeline A. K. McDowell I believe they can be unrelated in the following sense: definition of curvature only depends on the affine connection, but this does not require a metric on the manifold, so one may not even have a notion of geodesics. Of course, usually we compute Kretschmann scalar using the metric, so this point is not always clear.
Mar 9, 2020 at 14:29 history asked KayS CC BY-SA 4.0