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Apr 13, 2017 at 12:39 history edited CommunityBot
replaced http://physics.stackexchange.com/ with https://physics.stackexchange.com/
Oct 9, 2016 at 5:49 history edited Qmechanic
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Jul 20, 2016 at 5:53 history protected Qmechanic
Jul 20, 2016 at 5:40 answer added Mass timeline score: 7
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Feb 6, 2014 at 13:50 history edited Qmechanic
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Feb 11, 2013 at 9:51 vote accept Editortoise-Composerpent
Feb 9, 2013 at 20:29 history edited Qmechanic CC BY-SA 3.0
Dear Andrea Colonna, if u don't like my changes please roll back or use the parts u like.
Feb 9, 2013 at 20:17 answer added Qmechanic timeline score: 29
Feb 8, 2013 at 0:17 comment added Michael @AndreHolzner That's not what the OP is asking. The question is whether there are higher dimensional representations of the 4D Dirac algebra, i.e., looking for four matrices that satisfy the 4D algebra but which are larger than 4x4. The standard construction that you link to gives matrix dimensions which are powers of two, which doesn't answer the question of whether there are any 6x6 representations.
Feb 7, 2013 at 20:28 comment added Andre Holzner yes, it's definitively possible to have matrices larger than 4x4 satisfying the above relations, see this Wikipedia article and this link
Feb 7, 2013 at 19:09 history tweeted twitter.com/#!/StackPhysics/status/299595672506728448
Feb 7, 2013 at 16:21 comment added Michael Don't know if this is the way - just thinking out loud here - but the projection operators $P_{\pm} = (1\pm\gamma^5)/2$ cut the space in half, so if you can prove that $P_{\pm}$ can't have an odd number of nonzero eigenvalues you're done. You can probably use the representation theory of SU(2) to complete a proof since in four dimensions SO(3,1) ~ SU(2)xSU(2) (a double cover) and the projectors drop you onto one of the factors.
Feb 7, 2013 at 15:09 history asked Editortoise-Composerpent CC BY-SA 3.0