Timeline for Finding the conditions for a resonant (unique single mode) state in the wave equation
Current License: CC BY-SA 4.0
6 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Feb 17, 2020 at 0:49 | vote | accept | Marco Villalobos | ||
| Feb 17, 2020 at 0:48 | comment | added | Marco Villalobos | As you say, I get that the therm with n=2 blows up to infinity, in a real world scenario, with damping, maybe this amplitude is really really high, so the motion is basically this normal mode. Is this what I saw happening in the lab? | |
| Feb 16, 2020 at 16:06 | comment | added | mike stone | For any shaking you will get some excitation of the non-resonant modes. In the absence of damping and at $\omega= 2\pi n/L$ the resonant mode will have infinite amplitude, so you need to stay away from exact resonance. What do you actually get when you solve? | |
| Feb 16, 2020 at 14:33 | comment | added | Marco Villalobos | That's what I tried as I say in Edit2, but it also fails to give me an unique normal mode as a solution, probably that's because in this scenario the string is not fixed at both sides anymore, and we don't get the normal modes expected | |
| Feb 16, 2020 at 13:31 | history | edited | mike stone | CC BY-SA 4.0 |
added 253 characters in body
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| Feb 16, 2020 at 13:23 | history | answered | mike stone | CC BY-SA 4.0 |