Timeline for Do Feynman path integrals satisfy Bell locality assumption?
Current License: CC BY-SA 4.0
17 events
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| Feb 28, 2020 at 6:28 | history | edited | Jarek Duda | CC BY-SA 4.0 |
Improved text, added diagram
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| S Feb 25, 2020 at 13:01 | history | bounty ended | CommunityBot | ||
| S Feb 25, 2020 at 13:01 | history | notice removed | CommunityBot | ||
| Feb 20, 2020 at 15:32 | comment | added | Jarek Duda | @GuyInchbald, all e.g. Lagrangian formalism models (like EM, GR, QFT) are local realistic - naively satisfy Bell's assumptions, which lead to inequalities violated by physics - contradiction. I am asking if this issue can be resolved by solving them in symmetric way: least action principle, Feynman path/diagram ensemble. Boundary conditions are e.g. in minus and plus infinity, measurement is between them - to get its state we have to meet propagator from past and from future, each propagating some separate amplitude - kind of "hidden state". | |
| Feb 20, 2020 at 14:24 | comment | added | Guy Inchbald | @Jarek Duda Local realism and hidden-variable models are not necessarily the same thing. For example Bohm's hidden-variable "implicate order" model is compatible with the nonlocality demonstrated by tests of Bell's theorem. I think you may be able to clarify your question by removing all mention of hidden variables. | |
| Feb 20, 2020 at 13:59 | history | edited | Jarek Duda | CC BY-SA 4.0 |
boundary conditions remark
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| Feb 20, 2020 at 10:37 | comment | added | Jarek Duda | @Icv, in path integrals you find solution based on very different boundary conditions - this x,y you have writen, which are time symmetric: x is in the past, y is in the future. Beside Bell's hidden variable in 'x', there is not included additional information hidden in y - literally after the measurement. It is more intuitive to think about it using spatial symmetry instead - using Ising model which has nearly the same math: Feynman -> Boltzmann path ensemble. Please think about probability distribution inside Ising sequence - getting Pr(i)=(psi_i)^2 from symmetry (e.g. diagram above). | |
| Feb 20, 2020 at 9:25 | comment | added | lcv | Sorry Jarek but the question in bold makes no sense. Feynman path integral is simply a way to compute certain amplitudes, like $\langle x| e^{-i tH}| y \rangle$. It's not a different interpretation of quantum mechanics or anything like that. You can use whatever method you like to compute the ingredients that enter the Bell's theorem. Usually the latter is presented in CHSH form, i.e. for two qubits. Hence the computation boils down to computing expectation values of a $4\times 4$ matrix. Using the path integral (which for spin is not even rigorously defined) seems a bit a waste of resources. | |
| Feb 20, 2020 at 9:02 | answer | added | Eric David Kramer | timeline score: 0 | |
| Feb 17, 2020 at 14:04 | history | edited | Jarek Duda | CC BY-SA 4.0 |
Born rule from symmetry sketch of derivation
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| S Feb 17, 2020 at 11:23 | history | bounty started | Jarek Duda | ||
| S Feb 17, 2020 at 11:23 | history | notice added | Jarek Duda | Draw attention | |
| Feb 17, 2020 at 3:53 | answer | added | udifuchs | timeline score: 1 | |
| Feb 15, 2020 at 12:11 | history | edited | Jarek Duda | CC BY-SA 4.0 |
shortened title
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| Feb 15, 2020 at 11:59 | comment | added | Jarek Duda | @GuyInchbald, it ruled out if using Schrodinger equation - but here I ask what if physics solves QM using Feynman path integrals instead? In contrast to Schrodinger, path integrals are time symmetric, what is completely different - "hidden variables" are not just in the past, but in both past and future. We could transform such solution to Schrodinger, but its state would be already optimized for all future measurements - as in superdeterminism. | |
| Feb 15, 2020 at 11:40 | comment | added | Guy Inchbald | Does Bell's theorem rule out hidden-variable models? Experimental confirmation has ruled out local models, but AFAK there is nothing to prevent a nonlocal hidden-variable model. | |
| Feb 15, 2020 at 10:38 | history | asked | Jarek Duda | CC BY-SA 4.0 |