Timeline for Difference between electric field $\mathbf E$ and electric displacement field $\mathbf D$
Current License: CC BY-SA 2.5
8 events
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| Oct 23, 2022 at 9:52 | comment | added | Christophe | Funny that you start by saying "Like Marek has said above, the electric field 𝐸 is the fundamental field" while your whole answer shows in great details why and how he is actually wrong. | |
| Jul 10, 2020 at 19:33 | comment | added | N. Gin labs | @genneth Is $j$ current density? If so, please consider defining $J=\text{current density}$, (not sure why you used '$j$'), otherwise great answer +1 | |
| Sep 9, 2017 at 2:41 | comment | added | apdnu | Your point #2 is simply wrong, unless you mean "free charge" by Q. Gauss' law relates the flux of E through a closed surface to the total enclosed charge. By using Q without defining it explicitly as "free charge," you're going to confuse a lot of people. | |
| Feb 17, 2011 at 17:41 | comment | added | Marek | Yes, very good answer. Even if it strays a little away from the question... But personally I don't mind that at all :) | |
| Feb 17, 2011 at 17:32 | comment | added | Colin K | Wow, This really is a great answer. I thought I had a pretty good understanding of electrodynamics but you just explained this is a way I've never thought about it before. | |
| Feb 17, 2011 at 17:06 | comment | added | Platypus Lover | I think this is an awesome answer, +1! | |
| Feb 17, 2011 at 10:06 | history | edited | genneth | CC BY-SA 2.5 |
some more random additions; added 179 characters in body
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| Feb 16, 2011 at 22:09 | history | answered | genneth | CC BY-SA 2.5 |