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Dec 14, 2014 at 15:56 history edited Sam Bader CC BY-SA 3.0
Noted the error in my given example
Dec 26, 2013 at 22:02 answer added Jack Chi timeline score: 1
Sep 12, 2013 at 23:13 comment added Sam Bader Neumann boundary conditions on what quantity? If on $\theta$, I agree with you, but, as mentioned, part of the difficulty is trying to find any physical justification for those boundary conditions.
Sep 12, 2013 at 19:14 comment added jjcale Neumann boundary conditions imply that $\theta$ must be constant, see maths.qmul.ac.uk/~wjs/MTH5102/laplace10.pdf
Sep 12, 2013 at 15:53 vote accept Sam Bader
Feb 4, 2013 at 18:18 answer added Sam Bader timeline score: 1
Feb 4, 2013 at 13:09 history tweeted twitter.com/#!/StackPhysics/status/298417874379341824
Feb 3, 2013 at 23:35 history edited Sam Bader CC BY-SA 3.0
adjusted explaination of boundary condition
Feb 3, 2013 at 22:58 answer added emarti timeline score: 2
Feb 3, 2013 at 19:41 history edited Sam Bader CC BY-SA 3.0
added 10 characters in body
Feb 3, 2013 at 14:35 review First posts
Feb 3, 2013 at 14:39
Feb 3, 2013 at 14:23 history edited Sam Bader CC BY-SA 3.0
added 43 characters in body
Feb 3, 2013 at 14:17 history asked Sam Bader CC BY-SA 3.0