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Timeline for de Sitter cosmological limit

Current License: CC BY-SA 2.5

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Sep 9, 2012 at 6:00 comment added Columbia This answer is problematic and nonstandard. There are parts that are correct, parts that are false and parts that are pure speculation. Its better to keep things ordered by what happens classically, semiclassically and then in specific proposals of QG. Therefore I prefer Lubos' answer
Sep 9, 2012 at 3:10 comment added Ron Maimon The action you compute is meaningless, the imaginary part you are considering is nonsense, the emissions of a deSitter horizon is given by redshifting a local Unruh temperature of the near-horizon limit as always.
Sep 9, 2012 at 3:04 comment added Ron Maimon @lurscher: This answer is utter crap. He made up the physics of deSitter horizons--- this is not what happens, the "photon emission" is not emission, and it doesn't make the cosmological horizon go away. This is nonsense, -1, and please, please, unaccept it.
Feb 16, 2011 at 19:11 vote accept lurscher
Dec 31, 2017 at 5:52
Feb 16, 2011 at 18:56 comment added Lawrence B. Crowell I decided I got too ambitious with this and eliminated the end of this. It does not really appear to contribute that much. I also was pondering whether this actually worked. So I decided to clip it off.
Feb 16, 2011 at 18:54 history edited Lawrence B. Crowell CC BY-SA 2.5
added 269 characters in body
Feb 16, 2011 at 18:37 history edited Lawrence B. Crowell CC BY-SA 2.5
deleted 1782 characters in body
Feb 16, 2011 at 18:24 comment added MBN The last to lines are not clear. There are two integral signs with limits over $\Lambda$, and the integration to obtain the last line seems wrong?
Feb 16, 2011 at 18:15 comment added Gordon "The final fate of the universe can be computed"---I love it! But I thought that the answer was supposed to be 42 :)+1
Feb 16, 2011 at 17:53 history answered Lawrence B. Crowell CC BY-SA 2.5