Timeline for How does the current remain the same in a circuit?
Current License: CC BY-SA 4.0
10 events
when toggle format | what | by | license | comment | |
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Feb 6, 2020 at 11:37 | comment | added | Criticizing Israel not allowed | @ElFlea The sprocket only pulls on the chain links that are touching the sprocket, but that force gets distributed to the entire chain because all the chain links are connected. | |
Feb 6, 2020 at 11:34 | comment | added | El Flea | @user253751 So basically the voltage gives an average energy to all particles, rather than affecting just the ones near the power source? I guess in the bicycle example too, we (the bicyclers) will have to put in more energy to pedal than we would if we had to only move the top chain links, implying that the energy is "distributed" equally to all chain links (electrons, in circuit example). | |
Feb 6, 2020 at 11:32 | comment | added | Criticizing Israel not allowed | @user253751 The chain links are like the electrons. | |
Feb 6, 2020 at 11:31 | comment | added | El Flea | @user253751 I get this example, but I can't seem to relate it to the current situation. (No pun intended) | |
Feb 6, 2020 at 11:26 | comment | added | Criticizing Israel not allowed | @ElFlea Think of a bicycle chain (you've seen one, right?). Why are the top chain links moving? Because you pulled on them with the sprocket with the pedals. But why are the bottom chain links moving? Don't they have less energy? | |
Feb 6, 2020 at 11:17 | comment | added | El Flea | @user253751 But that's what is so confusing. 1) Why are the charges moving? Because of energy provided by the battery voltage. 2) If some of that energy is taken up by the lamp (the resistor), doesn't this mean that each electron has lesser energy now? And if the reason(i.e. energy provided by voltage) for the charges moving at all is decreased, then the charges will move slower? Right? | |
Feb 5, 2020 at 16:36 | comment | added | Criticizing Israel not allowed | @ElFlea Current is not velocity of charges, it is number of charges passing per second. If there are 100 charges going into the lamp per second and 90 charges coming out of the lamp per second then obviously 10 charges are getting stuck in the lamp every second. | |
Feb 5, 2020 at 8:41 | comment | added | Param_1729 | If velocity of charges decreases after it passes through the lamp then it would imply that the charges are being accumulated somewhere after the lamp but electrons repel each other so this is not possible. Hence the current in must be equal to current out. | |
Feb 5, 2020 at 8:25 | comment | added | El Flea | I don't get it. I am NOT talking about CHARGE. I am talking about CURRENT (which basically is how many electrons pass a point per sec). This "velocity" of the charges must decrease when energy is transferred from the electrons to the lamp, right? Obviously, charge is conserved, as there's a certain number of electrons/protons always. But CURRENT conserved? I don't understand. | |
Feb 5, 2020 at 8:18 | history | answered | niels nielsen | CC BY-SA 4.0 |