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Thomas Fritsch
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I would like to know if an object will fall towards the sun if its horizontal speed is 0$0$ at earthsearth's distance.

G = gravitational constant
m1 = mass of object = 70kg
m2 = mass of sun = 1.989 × 10^30 kg
r = Distance of object from sun = distance of earth to sun = 149.6*10^6 km

$G =$ gravitational constant
$m_1 =$ mass of object = 70 kg
$m_2 =$ mass of sun $= 1.989 \cdot 10^{30}$ kg
$r =$ Distance of object from sun = distance of earth to sun $= 149.6\cdot 10^6$ km

Assume there is no 'horizontal speed' (the velocity of m1$m_1$ tangent to r$r$) and there is nothing else in the solar system.

Does this mean that by using

F = Gm1m2/ r2

$$F = \frac{Gm_1m_2}{r^2}$$

There will be a Force of 0.4N$0.4$ N towards the sun applied to the object. Which means it will start to 'fall' towards the sun with acceleration of 0.0057m$0.0057 $ m/s^2s$^2$ (using F=ma$F=ma$)

In reality, does this mean a stationary (relative to the sun) astronaut at earth's distance will get pulled into the sun slowly?

I would like to know if an object will fall towards the sun if its horizontal speed is 0 at earths distance.

G = gravitational constant
m1 = mass of object = 70kg
m2 = mass of sun = 1.989 × 10^30 kg
r = Distance of object from sun = distance of earth to sun = 149.6*10^6 km

Assume there is no 'horizontal speed' (the velocity of m1 tangent to r) and there is nothing else in the solar system.

Does this mean that by using

F = Gm1m2/ r2

There will be a Force of 0.4N towards the sun applied to the object. Which means it will start to 'fall' towards the sun with acceleration of 0.0057m/s^2 (using F=ma)

In reality, does this mean a stationary (relative to the sun) astronaut at earth's distance will get pulled into the sun slowly?

I would like to know if an object will fall towards the sun if its horizontal speed is $0$ at earth's distance.

$G =$ gravitational constant
$m_1 =$ mass of object = 70 kg
$m_2 =$ mass of sun $= 1.989 \cdot 10^{30}$ kg
$r =$ Distance of object from sun = distance of earth to sun $= 149.6\cdot 10^6$ km

Assume there is no 'horizontal speed' (the velocity of $m_1$ tangent to $r$) and there is nothing else in the solar system.

Does this mean that by using

$$F = \frac{Gm_1m_2}{r^2}$$

There will be a Force of $0.4$ N towards the sun applied to the object. Which means it will start to 'fall' towards the sun with acceleration of $0.0057 $ m/s$^2$ (using $F=ma$)

In reality, does this mean a stationary (relative to the sun) astronaut at earth's distance will get pulled into the sun slowly?

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Qmechanic
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Will an object fall towards the sun if it not orbiting the sun?

I would like to know if an object will fall towards the sun if its horizontal speed is 0 at earths distance.

G = gravitational constant
m1 = mass of object = 70kg
m2 = mass of sun = 1.989 × 10^30 kg
r = Distance of object from sun = distance of earth to sun = 149.6*10^6 km

Assume there is no 'horizontal speed' (the velocity of m1 tangent to r) and there is nothing else in the solar system.

Does this mean that by using

F = Gm1m2/ r2

There will be a Force of 0.4N towards the sun applied to the object. Which means it will start to 'fall' towards the sun with acceleration of 0.0057m/s^2 (using F=ma)

In reality, does this mean a stationary (relative to the sun) astronaut at earth's distance will get pulled into the sun slowly?