Timeline for Why is the energy eigenstate of hydrogen atoms $\lvert n\ell ms \rangle$?
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Dec 5, 2021 at 6:01 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
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Nov 26, 2020 at 10:06 | history | bumped | CommunityBot | This question has answers that may be good or bad; the system has marked it active so that they can be reviewed. | |
Dec 4, 2019 at 20:00 | review | Close votes | |||
Dec 7, 2019 at 16:27 | |||||
Dec 4, 2019 at 19:55 | answer | added | ZeroTheHero | timeline score: 1 | |
Dec 4, 2019 at 19:43 | history | edited | DanielSank | CC BY-SA 4.0 |
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Dec 4, 2019 at 19:40 | answer | added | Kraigolas | timeline score: 0 | |
Dec 4, 2019 at 19:39 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
deleted 9 characters in body; edited tags; edited title
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Dec 4, 2019 at 17:56 | comment | added | march | You find $\Psi_{nlms}$ by solving the time-independent Schrodinger equation, which is the same as finding the eigenstates of the Hamiltonian, which are interpreted as states of definite energy (since the Hamiltonian is the energy operator). Therefore, we call them \emph{energy eigenstates}. | |
Dec 4, 2019 at 17:13 | comment | added | Danny Han | Thank you for your answer. What I don't understand is, how that results in the 'energy' eigenstates having n,l,m,s as parameters | |
Dec 4, 2019 at 16:47 | comment | added | John Rennie | The eigenfunctions factor into radial, angular and spin parts: $\Psi_{nlms} = \psi_n(r) Y_{lm}(\theta, \phi) \eta(s)$. | |
Dec 4, 2019 at 16:19 | history | asked | Danny Han | CC BY-SA 4.0 |