Timeline for Why the total virtual work done by forces from constraints vanishes? (Perpendicularity of two or more particles)
Current License: CC BY-SA 4.0
8 events
| when toggle format | what | by | license | comment | |
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| Nov 26, 2019 at 0:13 | comment | added | MST | Since motion is happening in 3-dimensional space, one can not have more than two constraints if you still want motion. For two constraints your motion is essentially 1-dimensional. | |
| Nov 25, 2019 at 22:55 | comment | added | Ma Joad | Okay. What about the case of two or more constraints? That cannot be seen as a surface... | |
| Nov 25, 2019 at 14:46 | comment | added | MST | Then it is still a surface, namely, the surface of the rod when the particles motion is constrained on the surface of this rod. Then you have to define your surface accordingly. | |
| Nov 25, 2019 at 14:45 | comment | added | MST | I have edited this sentence in order to make it more clear. In summary: the constrained motion is induced by constraining forces. | |
| Nov 25, 2019 at 14:43 | history | edited | MST | CC BY-SA 4.0 |
added 105 characters in body
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| Nov 25, 2019 at 14:35 | comment | added | Ma Joad | Also, what if it is not a surface? e.g. a rod | |
| Nov 25, 2019 at 14:34 | comment | added | Ma Joad | "a motion can constraint which result out of contraining forces" What does that mean? | |
| Nov 25, 2019 at 13:12 | history | answered | MST | CC BY-SA 4.0 |