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Nov 21, 2019 at 17:22 comment added Qmechanic Related: physics.stackexchange.com/q/38348/2451 and links therein.
Nov 21, 2019 at 17:19 answer added SK Dash timeline score: 1
Nov 21, 2019 at 17:03 comment added AccidentalTaylorExpansion The Euler Lagrange equations don't depend on initial conditions? Do you mean $\delta q(t_{initial}=\delta q(t_{final})=0$? The variation of $q$ has to be zero because any varied path should still match the boundary conditions but there are no restrictions on the B.C. of $q$.
Nov 21, 2019 at 16:57 history edited Qmechanic
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S Nov 21, 2019 at 16:56 history suggested alfred CC BY-SA 4.0
Improved the typography and corrected a few grammatical errors to make the question more comprehensible.
Nov 21, 2019 at 16:39 review Suggested edits
S Nov 21, 2019 at 16:56
Nov 21, 2019 at 16:30 review First posts
Nov 21, 2019 at 17:32
Nov 21, 2019 at 16:28 history asked Ioannis Papadopoulos CC BY-SA 4.0