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Nov 21, 2019 at 23:19 history edited S. McGrew CC BY-SA 4.0
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Nov 21, 2019 at 23:00 comment added Chappo Hasn't Forgotten @S.McGrew the explanation in your comment is excellent and deserves to be included in the answer itself, e.g. introduced by "A simple way of thinking about this is...". :-)
Nov 19, 2019 at 20:59 comment added S. McGrew Assuming the satellite has essentially no mass, so the spaceship needs to use its engines to keep going in a circular orbit around the satellite, then only special relativity applies. The spacecraft will perceive its received data rate as being a bit faster than the transmitter's data rate on the satellite. A way to know this is via the fact that a clock taken from the satellite to the spacecraft, then after a while brought back to the satellite, will lose a bit of time relative to a clock left on the satellite, but uploaded data is like clock ticks on the satellite.
Nov 19, 2019 at 20:46 comment added lalala Curvature. Typed while walking with a mobile. Sorry
Nov 19, 2019 at 19:46 comment added S. McGrew Not sure how to translate "curvqtire"
Nov 19, 2019 at 18:44 comment added lalala Basically you are sayibg data rate goes up, since curvqtire from a satelite can prob be neglected
Nov 19, 2019 at 18:26 history answered S. McGrew CC BY-SA 4.0