Timeline for What does vanishing critical mass exponent mean?
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| Nov 22, 2019 at 15:06 | comment | added | Monopole | Yes I'm referring to the critical exponent v. What I meant is that by using wegner-houghton equation, between N=6 to 10 I get the coupling fixed points as all zeros or so close to zero. Which once its substituted into the matrix to get the eigenvalues and consequently the exponents, it results with the same values but still N=11, 12, 14 gives around 0.69 which are close to the one obtained for N=5. (above mentioned N's in the question were obtained by using a different regulator) | |
| Nov 18, 2019 at 0:46 | comment | added | Seth Whitsitt | By "critical mass exponent," are you referring to the critical exponent $\nu$? This cannot be zero by definition. Its value for the $d=3$ O($N$) models is known do fairly good accuracy. | |
| Nov 16, 2019 at 14:11 | history | asked | Monopole | CC BY-SA 4.0 |