Timeline for Generalization to Rear-Wheel Steering?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 12, 2019 at 21:04 | vote | accept | DarkDrassher34 | ||
| Nov 12, 2019 at 20:53 | vote | accept | DarkDrassher34 | ||
| Nov 12, 2019 at 20:53 | |||||
| Nov 12, 2019 at 20:42 | history | edited | DarkDrassher34 | CC BY-SA 4.0 |
edited title
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| Nov 12, 2019 at 20:23 | answer | added | John Alexiou | timeline score: 1 | |
| Nov 12, 2019 at 20:19 | comment | added | DarkDrassher34 | Ok. What is the answer then? | |
| Nov 12, 2019 at 20:16 | comment | added | John Alexiou | This is two different questions actually. First given a path $(x,y)$ what is the tangent vector and radius of curvature. Second is given the radius of curvature and the geometry of a vehicle, what are the steering angles? The first one is a known problem in differential geometry and the second one is a geometry problem that requires simple trigonometry. | |
| Nov 12, 2019 at 20:05 | comment | added | DarkDrassher34 | You can assume that the point that is tracked by (x,y) is whichever makes the calculation the easiest. | |
| Nov 12, 2019 at 20:01 | comment | added | John Alexiou | What point of the vehicle is tracked by (x,y)? Kinematically the velocity vector is tangent to the path only at the point in the middle of the non-steering wheels. Otherwise a transformation would need to be applied to get the (x,y) of the non-steering side. Please provide a sketch with the important dimensions and locations called out. | |
| Nov 12, 2019 at 19:51 | history | asked | DarkDrassher34 | CC BY-SA 4.0 |