Timeline for How can kinetic energy increase during a collision?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 11, 2019 at 6:45 | comment | added | Farcher | The rest frame of the second particle (and the first particle) is an accelerated reference frame not an inertial reference frame. | |
| Nov 10, 2019 at 15:28 | comment | added | Bob D | @AaronStevens That may be, but I'm still trying to sort it out. E.g., is the 50% increase in KE seen from the original rest frame of the second particle, or is it as seen from the rest frame of the second particle. Seems it can't be the latter because if the relative velocity after the collision is root 2 x $v_o$ then the increase as seen from the second particle would be 100% | |
| Nov 10, 2019 at 15:13 | comment | added | BioPhysicist | I agree that kinetic energy of frame dependent. I don't think this problem has anything to do with that though. | |
| Nov 10, 2019 at 14:51 | comment | added | Bob D | @AaronStevens I'm sorry, but where did I say relative velocity is frame dependent? Although it might not apply to this collision example, I'm saying in general kinetic energy, and therefore change in kinetic energy, is frame dependent. Do you not agree? | |
| Nov 10, 2019 at 13:30 | comment | added | BioPhysicist | Which at that point there isn't a need for the collision in the first place. | |
| Nov 10, 2019 at 13:21 | comment | added | BioPhysicist | But relative velocity isn't frame dependent. No matter what frame you are in, you will still see the two objects have the same relative velocity. So really you think the question is asking "in what reference frame will you observe a $50\%$ increase in total kinetic energy"? And then are we assuming the collision is elastic? | |
| Nov 9, 2019 at 7:23 | history | undeleted | Bob D | ||
| Nov 9, 2019 at 7:23 | history | deleted | Bob D | via Vote | |
| Nov 9, 2019 at 7:22 | history | answered | Bob D | CC BY-SA 4.0 |