Timeline for In which situation does the electric field vary sinusoidally with position?
Current License: CC BY-SA 4.0
9 events
| when toggle format | what | by | license | comment | |
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| Oct 19, 2019 at 4:14 | comment | added | Bill N | @Knight No, a snapshot does not mean that the charge distribution which created the wave is static. Static means that the distribution is at rest at ALL times. The snapshot is a picture of the current values of the E-field at various locations due to all the previous motions of charges. | |
| Oct 18, 2019 at 6:54 | comment | added | user240696 | @BillN But as I say that picture is a snapshot and hence the charge is static and inverse square should be followed, isn't it? | |
| Oct 17, 2019 at 19:08 | comment | added | Bill N | @Knight $\int \vec{F}\cdot d\vec{r}$ is work. The graph is of an EM wave, not the field from a static point charge, as I say in my answer. You are only going to get an inverse square curve for E vs x with a static point charge. If you have a distribution of charges or moving charges, you won't get an inverse square relation for the total field. | |
| Oct 17, 2019 at 17:32 | comment | added | user240696 | @BillN I apologise for asking an off-topic question but can you please explain the thing in your about section. I mean I like to know how things $\int\vec{F}\cdot\vec{dr}$ | |
| Oct 17, 2019 at 17:27 | comment | added | user240696 | @BillN yes that’s only I’m saying. As we move along the c-axis the magnitude of electric field is increasing which is against the inverse square Law. | |
| Oct 17, 2019 at 17:22 | comment | added | Bill N | @Knight The lengths of the red arrows do not indicate position. They indicate the strength of the E-field at the C-axis location. Move to a different C-location and the E-field is different. | |
| Oct 17, 2019 at 16:12 | comment | added | BioPhysicist | @Knight Your picture shows vectors at points along the c-axis. Just because the arrows extend to above this axis does not mean the picture is showing the field at those points. Remember for a vector field a vector quantity is assigned to each point in space. In this diagram they have only shown the vectors at the points in space along the c-axis. | |
| Oct 17, 2019 at 16:09 | comment | added | user240696 | Your graph is depicting only one spatial dimension . Will not electric field change as it is shown? Kindly explain me, I need it. | |
| Oct 17, 2019 at 15:41 | history | answered | Bill N | CC BY-SA 4.0 |