Timeline for Finding commutators without cyclic permutations
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Oct 4, 2019 at 18:44 | comment | added | Alekxos | @G.Smith Thanks, I was aware of the contracted epsilon identity but not the simplification with no indices contracted. | |
| Oct 4, 2019 at 18:42 | comment | added | Alekxos | It may be simpler to write the problem in scalar indices rather than variable indices, but it would be nice if the notation itself captured that elegance. | |
| Oct 4, 2019 at 18:40 | comment | added | Marc Plana Caballero | Stating a problem in simpler terms (in this case using indices 1, 2, 3 and then permute indices) is awesomely elegant. | |
| Oct 4, 2019 at 17:30 | review | Close votes | |||
| Oct 27, 2019 at 12:04 | |||||
| Oct 4, 2019 at 17:13 | comment | added | G. Smith | See Wikipedia for how to reduce the product of two Levi-Civita symbols with no indices contracted. Look under Properties > Three dimensions > Product. | |
| Oct 4, 2019 at 17:04 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
edited body; edited tags
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| Oct 4, 2019 at 16:54 | history | asked | Alekxos | CC BY-SA 4.0 |