Timeline for Pair production in complete vacuum
Current License: CC BY-SA 3.0
13 events
when toggle format | what | by | license | comment | |
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Jan 15, 2013 at 4:49 | vote | accept | 71GA | ||
Jan 15, 2013 at 4:49 | comment | added | 71GA | Thats is the case yes. | |
Jan 14, 2013 at 7:33 | comment | added | DarenW | Just to be clear, you are assuming a single photon initially? | |
Jan 14, 2013 at 6:05 | answer | added | anna v | timeline score: 4 | |
Jan 13, 2013 at 23:31 | comment | added | 71GA | If you write some anwser i ll accept it as a solution. | |
Jan 13, 2013 at 18:15 | comment | added | anna v | mathworld.wolfram.com/ReductioadAbsurdum.html :"A method of proof which proceeds by stating a proposition and then showing that it results in a contradiction, thus demonstrating the proposition to be false" | |
Jan 13, 2013 at 18:08 | comment | added | anna v | You have already proven it yourself , it is called proof by "reductio ad absurdum" . When you reach conflicting solutions as you have, you have proven that the hypothesis, in this case that a real gamma can go into e+e-, is wrong. So you have proven it cannot. | |
Jan 13, 2013 at 12:00 | comment | added | anna v | But it is not possible to have pari production in vacuum. The photon needs to interact with another particle . | |
Jan 13, 2013 at 10:40 | comment | added | 71GA | Yes, but could someone than show me how can we mathematically derive WHY pair production in vacuum is posible? | |
S Jan 12, 2013 at 19:51 | history | suggested | Earth is a Spoon | CC BY-SA 3.0 |
fixed many spelling mistakes; added tags
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Jan 12, 2013 at 19:51 | review | Suggested edits | |||
S Jan 12, 2013 at 19:51 | |||||
Jan 12, 2013 at 14:54 | comment | added | anna v | It is due to the fact that the photon has 0 mass whereas the electron positron pair will have a positive invariant mass. A third particle is needed with which the photon can interact so as not to come to a paradox. | |
Jan 12, 2013 at 14:34 | history | asked | 71GA | CC BY-SA 3.0 |