Your formulas for calculating injection efficiency and the diode model are basically correct and the extraction of the series resistance is also correct but your analysis of the ideality factors is not quite right.
The radiative recombination slope is that small section right after the first slope that you highlighted in red (I highlighted it in green below). The second slope you drew at the top right is not correct… that’s well into the series resistance limited part of the diode behavior.
The curve shows that non-radiative recombination dominates in the region with the red slope and radiative recombination dominates on the green slope and in the series resistance limited portion. The injection efficiency should climb very quickly with voltage from the point where the two slopes start to diverge (about 2.3V).
The ideality factors are crazy high so there is something not quite right here. Your voltage scale seems to have some sort of offset of a realistic voltage. The clue is where the current is dropping to zero. It looks as though the zero of your voltage scale is at 1.5V but it's not an offset because that won't fix the ideality factors... it's both an offset and a scale factor.
Taking it at face value and using the notation in your link the two ideality factors are
$m_D = 3.08$ and $m_R = 4.81$
andI erased earlier values of the reverse saturation currents are
$I_{D0} = 3.6\cdot 10^{-18}$ and $I_{R0} = 9.6\cdot 10^{-15}$
If you plug those into your model along withbecause there is something not quite right about the series resistance itmeasured data. The zero of voltage across the LED should fitbe where the experimental curve well beyond V =measured data turns down vertically, at about 1.5V … but. This indicates a 1.5V offset to the voltage scale.
The idealities aren’t very sensible! Sensible ideality factors are in the range of 1 to 2. That translates to 2.3 units on your log scale current for every 60 mV (60 mV/decade) to 120 mV. You can ignore the IRs term in the model until the curve starts to bend away from the green slope (at about 2.6V) otherwise the solution is by iteration. There is essentially no voltage drop across the series resistance below this voltage.