In general, the vector sum of the external torques equals $\dfrac{\mathrm{d}\mathbf{L}}{\mathrm{d}t}$, the rate of change of the angular momentum vector. If your object is starting at rest, the instantaneous axis of rotation would be in the direction of $\dfrac{\mathrm{d}\mathbf{L}}{\mathrm{d}t}$. Otherwise, it would be in the direction of $\mathbf{L}$, which may be changing with time. Note: a torque relative to the centre of mass is given by $\mathbf{R} \times \mathbf{F}$ (vector product).

In general, the vector sum of the external torques equals $\mathrm{d}\mathbf{L}/\mathrm{d}t$, the rate of change of the angular momentum vector. If your object is starting at rest, the instantaneous axis of rotation will be in the direction of $\mathrm{d}\mathbf{L}/\mathrm{d}t$. Otherwise, it will be in the direction of $\mathbf{L}$, which may be changing with time. Note: a torque relative to the center of mass is given by $\mathbf{r}\times \mathbf{F}$ (vector product).

In general, the vector sum of the external torques equals dL/dt, the rate of change of the angular momentum vector. If your object is starting at rest, the instantaneous axis of rotation would be in the direction of dL/dt. Otherwise it would be in the direction of L, which may be changing with time. Note: a torque relative to the center of mass is given by R x F (vector product).

In general, the vector sum of the external torques equals $\dfrac{\mathrm{d}\mathbf{L}}{\mathrm{d}t}$, the rate of change of the angular momentum vector. If your object is starting at rest, the instantaneous axis of rotation would be in the direction of $\dfrac{\mathrm{d}\mathbf{L}}{\mathrm{d}t}$. Otherwise, it would be in the direction of $\mathbf{L}$, which may be changing with time. Note: a torque relative to the centre of mass is given by $\mathbf{R} \times \mathbf{F}$ (vector product).