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Nov 6, 2020 at 3:24 vote accept Dwagg
Jun 10, 2020 at 12:00 history tweeted twitter.com/StackPhysics/status/1270687160807587841
Jun 10, 2020 at 7:09 answer added Ruben Verresen timeline score: 6
Aug 24, 2019 at 3:05 comment added Dwagg @ChiralAnomaly Good question, I am not sure. Indeed gauge-fixing may not be required for finite groups, or the gauge redundancy may only contribute an overall factor. As for the second question-- yes, regardless, I can't understand how the path integral of a QFT with a finite gauge group relates to the path integral prescription for an orbifold theory, with all its twisted boundary conditions and such.
Aug 23, 2019 at 23:47 comment added Chiral Anomaly When the gauge group is finite, does computing the path-integral require fixing the gauge? If not, then does the question remain if gauge-fixing isn't used?
Aug 23, 2019 at 2:16 history asked Dwagg CC BY-SA 4.0