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Aug 3, 2019 at 14:16 comment added Ajay Shanmuga Sakthivasan Let us continue this discussion in chat.
Aug 3, 2019 at 14:04 comment added mavavilj So maybe "exact length" makes no sense, because the length can be "some". The other properties are meaningful.
Aug 3, 2019 at 14:03 comment added mavavilj By this calculator: engineersedge.com/calculators/comp_spring_k_pop.htm One'd think that the "length" of the spring is not related to $k$. Rather diameter of the wire, material of the wire and number of coils. But not spacing of coils.
Aug 3, 2019 at 13:58 comment added Ajay Shanmuga Sakthivasan @mavavilj Sure the physical properties of the spring affect k - the spring constant, but it doesn't affect c - damping coefficient (which depends on the medium in which the system is placed) and m - mass of the attached object. Generally the spring is assumed to be ideal, it doesn't have any mass on its own.
Aug 3, 2019 at 13:53 comment added mavavilj But I thought the length, width and the thickness of the spring ought to surely be influenced by $k,c,m$?
Aug 3, 2019 at 13:46 history edited Ajay Shanmuga Sakthivasan CC BY-SA 4.0
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Aug 3, 2019 at 13:43 comment added Ajay Shanmuga Sakthivasan @mavavilj The x in the equation F=-kx is the value by how much the spring the extended or compressed. If x=L, where L is the equilibrium length, F will just be zero. You can look up on Hooke's law for more on this. By drawing the spring, if you mean a graphical simulation, you can take it whatever you want.
Aug 3, 2019 at 13:37 comment added mavavilj If I want to draw the spring?
Aug 3, 2019 at 13:37 comment added Ajay Shanmuga Sakthivasan @mavavilj If you look the code carefully, they're taking the initial displacement as 0.3 units and initial velocity as 0 units. There's no need for you to know the the length (by which I think you mean the total of length of the spring?). But there's a subtle assumption that the spring is linear with the given displacement (normally this is the case when the displacement is small when compared to the total length of the spring).
Aug 3, 2019 at 13:37 comment added mavavilj There exists a relationship between the spring constant and some length, $k=-\frac{F}{x}=-\frac{F}{L}=-\frac{mg}{L}$. But I'm not sure if this $x=L$ is the equilibrium length (no compression, no stretch) or something else.
Aug 3, 2019 at 13:29 comment added mavavilj As given here: adamwermus.wordpress.com/2016/01/22/…. The model does produce movement of the object at the end of the spring, but I have no idea what the lengths of the springs are.
Aug 3, 2019 at 13:25 history answered Ajay Shanmuga Sakthivasan CC BY-SA 4.0