Timeline for Can I discover the intial length/dimensions of spring from $mx''+cx'+kx=0$?
Current License: CC BY-SA 4.0
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Aug 3, 2019 at 14:16 | comment | added | Ajay Shanmuga Sakthivasan | Let us continue this discussion in chat. | |
Aug 3, 2019 at 14:04 | comment | added | mavavilj | So maybe "exact length" makes no sense, because the length can be "some". The other properties are meaningful. | |
Aug 3, 2019 at 14:03 | comment | added | mavavilj | By this calculator: engineersedge.com/calculators/comp_spring_k_pop.htm One'd think that the "length" of the spring is not related to $k$. Rather diameter of the wire, material of the wire and number of coils. But not spacing of coils. | |
Aug 3, 2019 at 13:58 | comment | added | Ajay Shanmuga Sakthivasan | @mavavilj Sure the physical properties of the spring affect k - the spring constant, but it doesn't affect c - damping coefficient (which depends on the medium in which the system is placed) and m - mass of the attached object. Generally the spring is assumed to be ideal, it doesn't have any mass on its own. | |
Aug 3, 2019 at 13:53 | comment | added | mavavilj | But I thought the length, width and the thickness of the spring ought to surely be influenced by $k,c,m$? | |
Aug 3, 2019 at 13:46 | history | edited | Ajay Shanmuga Sakthivasan | CC BY-SA 4.0 |
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Aug 3, 2019 at 13:43 | comment | added | Ajay Shanmuga Sakthivasan | @mavavilj The x in the equation F=-kx is the value by how much the spring the extended or compressed. If x=L, where L is the equilibrium length, F will just be zero. You can look up on Hooke's law for more on this. By drawing the spring, if you mean a graphical simulation, you can take it whatever you want. | |
Aug 3, 2019 at 13:37 | comment | added | mavavilj | If I want to draw the spring? | |
Aug 3, 2019 at 13:37 | comment | added | Ajay Shanmuga Sakthivasan | @mavavilj If you look the code carefully, they're taking the initial displacement as 0.3 units and initial velocity as 0 units. There's no need for you to know the the length (by which I think you mean the total of length of the spring?). But there's a subtle assumption that the spring is linear with the given displacement (normally this is the case when the displacement is small when compared to the total length of the spring). | |
Aug 3, 2019 at 13:37 | comment | added | mavavilj | There exists a relationship between the spring constant and some length, $k=-\frac{F}{x}=-\frac{F}{L}=-\frac{mg}{L}$. But I'm not sure if this $x=L$ is the equilibrium length (no compression, no stretch) or something else. | |
Aug 3, 2019 at 13:29 | comment | added | mavavilj | As given here: adamwermus.wordpress.com/2016/01/22/…. The model does produce movement of the object at the end of the spring, but I have no idea what the lengths of the springs are. | |
Aug 3, 2019 at 13:25 | history | answered | Ajay Shanmuga Sakthivasan | CC BY-SA 4.0 |