Timeline for Why is usual matter made up of $n,p$ and $e^-$?
Current License: CC BY-SA 4.0
7 events
| when toggle format | what | by | license | comment | |
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| Jul 29, 2019 at 18:33 | comment | added | MadMax | @Heterotic, "All three types of neutrinos are around us in great abundance and they are absolutely part of "ordinary matter" (as opposed for example to dark matter)." If there are right-handed (sterile) neutrinos, they can have humongous Majorana masses. They are thus "clumpable" by sheer gravity instead of being relativistic/hot. Hence they are possible cold dark matter candidates. | |
| Jul 29, 2019 at 17:43 | comment | added | Heterotic | @mithusengupta123 Yes, correct. They do not have strong interactions either, so they do not combine to form particles such as mesons and baryons either. | |
| Jul 29, 2019 at 13:46 | vote | accept | Solidification | ||
| Jul 29, 2019 at 13:46 | comment | added | Solidification | "because they do not have any electric charge." And also strong interactions? | |
| Jul 29, 2019 at 3:48 | comment | added | anna v | I would like to add to this correct answer that all the particles you list, in contrast to atoms and molecules , are only seen by the fit of mathematical formula's to measurements. These formulas are very successful in fitting data in the microcosm, and predicting new data. We treat the particles they hypothesize as we treat the ones we can find in chemical reactions. | |
| Jul 28, 2019 at 20:37 | comment | added | Cosmas Zachos | Solid answer. To the OP's trailing question in 2., I'd point out that the mass difference of the s quark from that of the u is over 90MeV, so it can not be offset/fudged by nuclear binding energies to prevent the inevitable weak decay of one to the other. | |
| Jul 28, 2019 at 19:13 | history | answered | Heterotic | CC BY-SA 4.0 |