Timeline for The value of $E$ in the LHS of Gauss law equation
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jul 7, 2019 at 20:43 | vote | accept | p0803 | ||
| Jul 6, 2019 at 12:47 | vote | accept | p0803 | ||
| Jul 7, 2019 at 20:43 | |||||
| Jul 6, 2019 at 12:32 | comment | added | BioPhysicist | @p0803 Just because two integrands are different doesn't mean their integrals over the same region must be different. Ex: $$\int_0^1x\text dx=\int_0^1\frac32x^2\text dx=\frac12$$ | |
| Jul 6, 2019 at 12:26 | comment | added | p0803 | your first statement is clear but in the second statement you say that value of field at points on the surface, when we add up the field due to the charges outside as well as due to the enclosed charge is not the same as the value of field when we were to consider only the enclosed charge but still the flux of E in both the cases is equal how could this be when the integral when calculating flux only contains E with the dot product of the surface element ,Then how could both the integrals give the same value if the value of E is different in both but the integral of area is equal in both? Thx | |
| Jul 6, 2019 at 11:59 | history | answered | BioPhysicist | CC BY-SA 4.0 |