Skip to main content
Physics

Return to Answer

added 63 characters in body
Source Link
Archisman Panigrahi
Archisman Panigrahi
  • 3.3k
  • 21
  • 41

The work energy theorem is a special case of the first law of thermodynamics, which says, "Heat given to the system + work done on the system = change in internal energy of the system"

When heat given to the system is zero, this becomes "change in internal energy (kinetic energy) = work done by external forces"

In this case, if we take the battery and the capacitor as a single system, no external work is being done on it. The heat given to the system is negative of the net heat released = -$CV^2/2$, which is also the change in internal energy of the battery + capacitor system. (Battery is losing energy $CV^2$, capacitor is gaining energy $CV^2/2$)

You can also consider the battery and the capacitors as different systems and use the above arguments to find the heat released, work done, and change in internal energy in each of them separately.

Also, there is no convention of "work done by heat energy".

The work energy theorem is a special case of the first law of thermodynamics, which says, "Heat given to the system + work done on the system = change in internal energy of the system"

When heat given to the system is zero, this becomes "change in internal energy (kinetic energy) = work done by external forces"

In this case, if we take the battery and the capacitor as a single system, no external work is being done on it. The heat given to the system is negative of the net heat released = -$CV^2/2$, which is also the change in internal energy of the battery + capacitor system. (Battery is losing energy $CV^2$, capacitor is gaining energy $CV^2/2$)

You can also consider the battery and the capacitors as different systems and use the above arguments to find the heat released, work done, and change in internal energy in each of them separately.

The work energy theorem is a special case of the first law of thermodynamics, which says, "Heat given to the system + work done on the system = change in internal energy of the system"

When heat given to the system is zero, this becomes "change in internal energy (kinetic energy) = work done by external forces"

In this case, if we take the battery and the capacitor as a single system, no external work is being done on it. The heat given to the system is negative of the net heat released = -$CV^2/2$, which is also the change in internal energy of the battery + capacitor system. (Battery is losing energy $CV^2$, capacitor is gaining energy $CV^2/2$)

You can also consider the battery and the capacitors as different systems and use the above arguments to find the heat released, work done, and change in internal energy in each of them separately.

Also, there is no convention of "work done by heat energy".

Source Link
Archisman Panigrahi
Archisman Panigrahi
  • 3.3k
  • 21
  • 41

The work energy theorem is a special case of the first law of thermodynamics, which says, "Heat given to the system + work done on the system = change in internal energy of the system"

When heat given to the system is zero, this becomes "change in internal energy (kinetic energy) = work done by external forces"

In this case, if we take the battery and the capacitor as a single system, no external work is being done on it. The heat given to the system is negative of the net heat released = -$CV^2/2$, which is also the change in internal energy of the battery + capacitor system. (Battery is losing energy $CV^2$, capacitor is gaining energy $CV^2/2$)

You can also consider the battery and the capacitors as different systems and use the above arguments to find the heat released, work done, and change in internal energy in each of them separately.