Skip to main content

Timeline for Is a partial trace cyclic?

Current License: CC BY-SA 4.0

6 events
when toggle format what by license comment
Jul 2, 2019 at 17:02 vote accept João Bravo
Jul 2, 2019 at 17:02 comment added João Bravo Yeah makes sense. Thank you
Jul 2, 2019 at 14:42 comment added doetoe The only thing that you can do (if I didn't make a mistake) is $$\operatorname{tr}_B[(A_1\otimes B_1B_2)\rho_{AB}] = \operatorname{tr}_B[(A_1\otimes B_2)\rho_{AB}(I\otimes B_1)].$$ This can be seen by writing $\rho_{AB}$ as a sum of pure tensors and using the linearity of the partial trace.
Jul 2, 2019 at 11:48 comment added João Bravo One question though. In this trace $$tr_B [(A_1 \otimes B_1 B_2) \ \rho_{AB}]$$ if $\rho_{AB}$ is not pure (aka cannot be written as a tensor product $\rho_{AB} =\rho_{A} \otimes \rho_{B}$), can we cycle anything?
Jul 2, 2019 at 11:45 comment added João Bravo Ah of course! Very clear answer, thank you :)
Jul 1, 2019 at 23:22 history answered doetoe CC BY-SA 4.0