Timeline for Are the plates of a battery really charged?
Current License: CC BY-SA 4.0
19 events
| when toggle format | what | by | license | comment | |
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| Apr 29, 2022 at 5:31 | comment | added | tryingtobeastoic | I have understood from Dale's answer how the Zn electrode is negatively charged. I'm still a bit confused as to how the Cu electrode is positively charged electrostatically. Is it appropriate to say that the Cu electrode too is also negatively charged, but it is less negatively charged than the Zn electrode? | |
| Jun 30, 2019 at 20:24 | history | edited | Alfred Centauri | CC BY-SA 4.0 |
added 1049 characters in body
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| Jun 30, 2019 at 18:39 | comment | added | Poutnik | The answer to your last question depends on the electrode capacitance what is not trivial to determine. | |
| Jun 30, 2019 at 18:37 | comment | added | Poutnik | Voltage is current dependent due limited rate of kinetics of chemical reactions and ion diffusion. This affects formation of several internal cell potential differences, acting against the cell voltage. It is effectively manifested as the (variable) cell internal resistance. | |
| Jun 30, 2019 at 18:31 | comment | added | mohamed azaiez | @Poutnik and Alfred sorry i cannot like your posts ( 13 rep points) but thanks for making me understand .and last question is how many charges that both electrode can hold before the reactions coming to a halt that determines the voltage ? | |
| Jun 30, 2019 at 18:16 | comment | added | mohamed azaiez | And can we say that the reaction still undergoes "short duration halts even when in a circuit | |
| Jun 30, 2019 at 18:15 | comment | added | mohamed azaiez | Thanks guys you are really helpful so if the charges go out faster (short circuit) the cell chemical reaction will 'speed up' zinc will more rapidly disolve and the battery life team will be reduced but voltage will stay the same at a high current | |
| Jun 30, 2019 at 17:46 | comment | added | Alfred Centauri | @mohamedazaiez, that is, only a tiny fraction of the energy stored in the reactants is used to initially charge the plates to the open-circuit voltage. Unlike a capacitor, the energy stored in the cell is in the form of chemical energy rather than electrostatic energy. Now that I better understand what you've asked, I think I'll edit my answer to explicitly address this. | |
| Jun 30, 2019 at 17:42 | comment | added | Poutnik | Equal rates mean motion of ions from electrode to solution and vice versa is ongoing by the same speed. If solution and metal were made from different isotopes, it would be observed they intermixed. Thermodynamic equilibrium = mechanical + thermal + chemical + radiation equilibrium, with dG=0 ( G is Gibbs energy or also called free anthalpy ). See TD equilibrium | |
| Jun 30, 2019 at 17:39 | comment | added | Alfred Centauri | @mohamedazaiez, why do you think this way (referring to 1st comment)? Are you thinking that the chemical reactants are exhausted and so cannot continue when the external circuit is connected? In my answer, I explicitly write that when the external circuit is connected, the reactions continue. | |
| Jun 30, 2019 at 17:39 | comment | added | mohamed azaiez | Ohhhhh i think i got it | |
| Jun 30, 2019 at 17:36 | comment | added | mohamed azaiez | @Poutnik What do you mean by to have equal rates and thermo dynamic equilibrium , thanks | |
| Jun 30, 2019 at 17:35 | comment | added | Poutnik | I see, I must have misread it somehow. | |
| Jun 30, 2019 at 17:33 | comment | added | Alfred Centauri | @Poutnik, thus the scare quotes around halts and the parenthetical (net) | |
| Jun 30, 2019 at 17:20 | comment | added | mohamed azaiez | Yeah but the negative terminal won t be charged anymore due to all excess charges going in the circuit it wont be like a capacitor anymore more like an electron pumping device | |
| Jun 30, 2019 at 17:17 | comment | added | Poutnik | In fact, it does not halt the reactions, it just makes the opposite reactions to have equal rate, forming thermodynamic equilibrium. | |
| Jun 30, 2019 at 16:23 | vote | accept | mohamed azaiez | ||
| Jun 30, 2019 at 18:59 | |||||
| Jun 30, 2019 at 15:54 | comment | added | mohamed azaiez | OK but when we connect both terminals with a circuit wouldn't all the excess charge simply flow in the wire and terminals become neutral again ? | |
| Jun 30, 2019 at 15:41 | history | answered | Alfred Centauri | CC BY-SA 4.0 |