Timeline for Moment of Inertia for Arbitrary Shape
Current License: CC BY-SA 4.0
10 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jun 15, 2019 at 14:22 | comment | added | fullnitrous | how okay? I need my calculations to be 100% correct I'm making a simulation. | |
| Jun 15, 2019 at 13:55 | comment | added | Sparsh Mishra | @fullnitrous It seems okay to me. | |
| Jun 14, 2019 at 17:14 | comment | added | fullnitrous | Forgot to write it but the origin is the center of mass of the rod. | |
| Jun 14, 2019 at 16:08 | comment | added | fullnitrous | Is this imgur.com/a/XvPCNgR correct in that case? The goal in the calculation was to only express the rotational kinetic energy of the rod by calculating the inertia tensor and the angular velocity. | |
| Jun 14, 2019 at 11:09 | comment | added | Sparsh Mishra | So, you can use the axes you mentioned, but you may then have to use the inertia tensor in a form that is not diagonal and it'll make the computation harder(because you said that the density can have any form and so it's not rotationally symmetric). Finding the inertia tensor, finding 3 directions that make it diagonal and then using those axes will be much better. Then you can use rotations about these axes to give the rotational kinetic energy. The total kinetic energy will be that plus the translational kinetic energy of the CoM. | |
| Jun 14, 2019 at 10:01 | comment | added | fullnitrous | It's a 3 dimensional rod and so is the density function. Technically the density function could form any shape within the limits of the cylinder. | |
| Jun 14, 2019 at 0:48 | comment | added | Sparsh Mishra | Is the rod 3 dimensional or does it just have a length and no thickness(ideal rod)? | |
| Jun 13, 2019 at 15:59 | comment | added | fullnitrous | Note -- the roll and yaw angles are aligned initially so it is in gimbal lock. The yaw angle is rotation around the global y axis while roll rotation is the axis that is the centre line of the rod. | |
| Jun 13, 2019 at 15:43 | comment | added | fullnitrous | Yes, sorry for asking further but. How would I apply this to a rod with the roll, pitch and yaw angles. The kinetic rotational energy must be described with these angles so it can be put into a Lagrangian equation so i get the equations of motion for those angles. Simply put -- the center of mass and mass of a rod is calculated with a triple integral of the density function of the rod. What is the rotational kinetic energy using only the roll pitch and yaw angles? Also the total rotational kinetic energy plus the total linear kinetic energy must equal the total kinetic energy right? | |
| Jun 13, 2019 at 13:09 | history | answered | Sparsh Mishra | CC BY-SA 4.0 |