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Jun 15, 2019 at 10:36 comment added Qmechanic Think of $(2\pi)^4$ as a normalization convention.
Jun 15, 2019 at 10:33 comment added Konstantinov Konstantin Thanks for your answer! Ok, that makes sense. It doesnt explain the $2\pi$-terms however. Do you know how come this matrix is used when calculating scattering? As opposed to the off-shell one.
Jun 5, 2019 at 9:50 history answered Qmechanic CC BY-SA 4.0