Timeline for Distance from ground to start suicide burn with initial height [closed]
Current License: CC BY-SA 4.0
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May 31, 2019 at 16:22 | history | closed |
Kyle Kanos John Rennie Jon Custer GiorgioP-DoomsdayClockIsAt-90 Yashas |
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May 25, 2019 at 7:07 | history | edited | dmoody256 | CC BY-SA 4.0 |
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May 25, 2019 at 6:19 | vote | accept | dmoody256 | ||
May 25, 2019 at 4:39 | history | edited | dmoody256 | CC BY-SA 4.0 |
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May 25, 2019 at 2:50 | answer | added | Cort Ammon | timeline score: 0 | |
May 25, 2019 at 2:07 | history | edited | dmoody256 | CC BY-SA 4.0 |
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May 25, 2019 at 2:05 | review | Close votes | |||
May 31, 2019 at 16:22 | |||||
May 25, 2019 at 2:02 | comment | added | dmoody256 | I reorganized the question so it is easier to understand. | |
May 25, 2019 at 2:02 | history | edited | dmoody256 | CC BY-SA 4.0 |
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May 25, 2019 at 1:55 | history | edited | dmoody256 | CC BY-SA 4.0 |
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May 25, 2019 at 1:45 | history | edited | dmoody256 | CC BY-SA 4.0 |
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May 25, 2019 at 1:41 | comment | added | dmoody256 | It's named that because you wait till the last possible moment to decelerate, and if you calculations are off, well then you've killed your self. space.stackexchange.com/a/10308/29963 | |
May 25, 2019 at 0:56 | comment | added | Cort Ammon | Ahh.,.. That's what I was looking for -- I didn't see the constrant of having 0 velocity at the ground. Usually that kind of thing is mentioned up front. Also... isnt' that the absolute opposite of a "suicide burn?" The entire purpose of such a burn is to avoid suicide? | |
May 25, 2019 at 0:55 | comment | added | dmoody256 | It's doesnt fall after a burn. It falls for some distance and then needs to burn once with constant thrust to reach exactly zero velocity at exactly when it reaches the ground. | |
May 25, 2019 at 0:51 | comment | added | Cort Ammon | As best as I can tell from the information you've given, there's no relationship between height and burn distance . If you construct a scenario where it burns for 1m, then falls for 3m, there's a comparable scenario where it burns for 1m and falls for 4m -- it just has to fall for a longer period of time. There's also a scenario where it burns for 2m then falls for 3m. | |
May 25, 2019 at 0:37 | comment | added | dmoody256 | I mean burn distance instead of burn time in the previous comment | |
May 25, 2019 at 0:31 | comment | added | dmoody256 | Nothing was given, I was just exploring the relationship with height and burn time. I was wanting to plot the relationship on a graphs with such an expression, swapping out gravity and thrust as constants. | |
May 24, 2019 at 23:21 | comment | added | Cort Ammon | On an unrelated note, it pains me so much to see rocketry problems which say "ignore changes in mass." It always feels like "How long can you stay underwater; ignore the fact that you need to breathe." | |
May 24, 2019 at 23:19 | comment | added | Cort Ammon | You say you are trying to calculate $d_b$, but what values are given? If you are given $h$ and $d_f$, then it is trivial without any physics at all. If you aren't given them, then you're going to need to some other constraint, like a fixed burn time. | |
May 24, 2019 at 22:45 | review | First posts | |||
May 25, 2019 at 1:45 | |||||
May 24, 2019 at 22:43 | history | asked | dmoody256 | CC BY-SA 4.0 |