Timeline for Why there is a negative sign in the formula of calculating work done in electrostatics?
Current License: CC BY-SA 4.0
4 events
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| May 24, 2019 at 17:03 | comment | added | Hawkingo | @unique As I said in my question, I am not talking about the sign of the work done but the sign in the equation which is eventually cancelled out by another negative sign originated by the integration of the dr over the path(when charge is moving towards the field/test charge) | |
| May 24, 2019 at 17:01 | comment | added | Hawkingo | @garyp I know the subject, in fact the same thing is written in also different physics books for example electricity and Magnetism by E. Purcell. | |
| May 24, 2019 at 16:47 | comment | added | garyp | Yes. Definitions of (change of) potential energy in terms of work done by an external force lead to problems, confusion (such as that generated by Feynman), the need to invoke Newton's third law, the need to add some wording about how the force is applied (constant v? quasistatic?) , the need to specify that no other forces are acting, and the need to consider phenomena outside of the system in question (the external force). BTW, there are a lot of things in Feynman that need to be ignored or glossed over. Unfortunately, you need to know the subject in advance to know which things. | |
| May 24, 2019 at 16:27 | history | answered | Shreyansh Pathak | CC BY-SA 4.0 |