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May 25, 2019 at 13:56 answer added Bob D timeline score: 0
May 24, 2019 at 16:33 comment added The Photon it isn't the applied force it is the "electrical force". Please see my answer.
May 24, 2019 at 16:29 answer added The Photon timeline score: 3
May 24, 2019 at 16:27 answer added Shreyansh Pathak timeline score: 0
May 24, 2019 at 16:17 history edited Hawkingo CC BY-SA 4.0
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May 24, 2019 at 16:13 history edited Qmechanic CC BY-SA 4.0
added 2 characters in body; edited title; edited tags
May 24, 2019 at 16:12 history reopened Qmechanic
May 24, 2019 at 16:09 comment added Hawkingo Then if I change the coordinate, for example, the other charge is moving in q3 quadrant ( in 2 dimensions, (x and y are negative)) then the dr will be positive, so how can a formula change /depends on a coordinate?
May 24, 2019 at 16:06 history edited Hawkingo CC BY-SA 4.0
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May 24, 2019 at 16:01 comment added Hawkingo The $ \vec { F}$ here is the applied force
May 24, 2019 at 16:01 history closed Qmechanic Needs details or clarity
May 24, 2019 at 16:00 comment added The Photon How is $\vec{F}$ defined in this problem?
May 24, 2019 at 15:30 answer added PhysicsMan timeline score: 0
May 24, 2019 at 15:14 history asked Hawkingo CC BY-SA 4.0