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Jun 4, 2020 at 16:03 history edited CommunityBot
Commonmark migration
May 17, 2019 at 11:11 comment added David Hammen Re Changing the numerical value of $k$ would make the speed totally different: In the expression $S = k\,\ln\Omega$, the $S$ on the left hand side has nothing to do with speed. That $S$ instead represents entropy, which has units of energy/temperature.
May 15, 2019 at 21:43 answer added Krup'a timeline score: 3
May 15, 2019 at 21:25 comment added acarturk Guessing but the definition of temperature probably depends on the arbitrary value of the Boltzmann constant. If this dependence is as $\textbf{K} \cdot k_B = $const. (in Joules) his would make the temperature dependent terms invariant under arbitrary constant selection.
May 15, 2019 at 20:52 history edited Abo Rakan CC BY-SA 4.0
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May 15, 2019 at 20:38 history edited Abo Rakan CC BY-SA 4.0
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May 15, 2019 at 20:35 history edited Qmechanic
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May 15, 2019 at 20:33 history edited Abo Rakan CC BY-SA 4.0
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S May 15, 2019 at 20:31 history suggested MarianD CC BY-SA 4.0
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May 15, 2019 at 20:10 review Suggested edits
S May 15, 2019 at 20:31
May 15, 2019 at 20:10 history edited Abo Rakan CC BY-SA 4.0
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May 15, 2019 at 20:00 history edited Abo Rakan CC BY-SA 4.0
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May 15, 2019 at 19:55 review First posts
May 15, 2019 at 20:45
May 15, 2019 at 19:54 history asked Abo Rakan CC BY-SA 4.0