Timeline for How to calculate the gravitational binding energy of a uniform cube of length $L$ and mass $M$?
Current License: CC BY-SA 4.0
11 events
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Aug 13, 2021 at 22:24 | comment | added | uhoh | @patta which reminds me of somewhat related: Another way to evaluate the gravitational force from a uniform cube? | |
May 14, 2019 at 4:34 | answer | added | G. Smith | timeline score: 3 | |
May 14, 2019 at 2:50 | comment | added | G. Smith | More accurately, $Q=-0.941156...$. | |
May 14, 2019 at 0:11 | comment | added | G. Smith | The three integrals over either $\mathbf{x}$ or $\mathbf{y}$ can be done analytically to get the gravitational potential of the cube. See arxiv.org/abs/1206.3857. I haven't been able to then integrate this potential over the cube to get the binding energy, but I was able to numerically integrate it and again get -0.941... . | |
May 13, 2019 at 23:09 | comment | added | G. Smith | I did a Monte-Carlo evaluation of $Q$ and found that it is between -0.941 and -0.942. | |
May 13, 2019 at 16:43 | history | edited | Qmechanic♦ | CC BY-SA 4.0 |
edited tags; edited title
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S May 13, 2019 at 15:50 | history | edited | Rian | CC BY-SA 4.0 |
Picture instead of link
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S May 13, 2019 at 15:50 | history | suggested | MarianD | CC BY-SA 4.0 |
Picture instead of link
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May 13, 2019 at 15:31 | review | Suggested edits | |||
S May 13, 2019 at 15:50 | |||||
May 13, 2019 at 15:25 | comment | added | patta | In the 21st century, go numerically. Or google it, probably somebody in the 19th century has done it analitycally | |
May 13, 2019 at 15:18 | history | asked | Rian | CC BY-SA 4.0 |