Skip to main content
11 events
when toggle format what by license comment
Aug 13, 2021 at 22:24 comment added uhoh @patta which reminds me of somewhat related: Another way to evaluate the gravitational force from a uniform cube?
May 14, 2019 at 4:34 answer added G. Smith timeline score: 3
May 14, 2019 at 2:50 comment added G. Smith More accurately, $Q=-0.941156...$.
May 14, 2019 at 0:11 comment added G. Smith The three integrals over either $\mathbf{x}$ or $\mathbf{y}$ can be done analytically to get the gravitational potential of the cube. See arxiv.org/abs/1206.3857. I haven't been able to then integrate this potential over the cube to get the binding energy, but I was able to numerically integrate it and again get -0.941... .
May 13, 2019 at 23:09 comment added G. Smith I did a Monte-Carlo evaluation of $Q$ and found that it is between -0.941 and -0.942.
May 13, 2019 at 16:43 history edited Qmechanic CC BY-SA 4.0
edited tags; edited title
S May 13, 2019 at 15:50 history edited Rian CC BY-SA 4.0
Picture instead of link
S May 13, 2019 at 15:50 history suggested MarianD CC BY-SA 4.0
Picture instead of link
May 13, 2019 at 15:31 review Suggested edits
S May 13, 2019 at 15:50
May 13, 2019 at 15:25 comment added patta In the 21st century, go numerically. Or google it, probably somebody in the 19th century has done it analitycally
May 13, 2019 at 15:18 history asked Rian CC BY-SA 4.0