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May 1, 2019 at 21:45 comment added Cinaed Simson Check out the Born Square - or better Google for the Enhanced Born Square.
May 1, 2019 at 21:43 comment added J. Murray @GiorgioP Thanks, I fixed the first part. I’m not sure I understand your second point, though. I agree that pV is a valid thermodynamic potential, but my point was that thermodynamic potentials are not functions of one another, but rather are obtained from one another by Legendre transform.
May 1, 2019 at 21:39 history edited J. Murray CC BY-SA 4.0
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May 1, 2019 at 21:31 comment added GiorgioP-DoomsdayClockIsAt-90 $U$ is just proportional to $T$ only in the case of perfect gases. However, the fomula defining the Helmholtz free energy has much broader validity than for perfect gases. Also making differences between thermodynamic variables and potentials is not clarifying. Think for example $pV$: as a function of $(V,T,\mu)$ it is a thermodynamic potential.
May 1, 2019 at 21:01 history answered J. Murray CC BY-SA 4.0