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May 3, 2019 at 11:02 history bounty ended CommunityBot
Apr 29, 2019 at 10:39 comment added ohneVal It is true that the factor 1/2 relies on the surface being closed, but the averaging is generic, it is only useful if you actually need to assign a value of the field exactly at an interface, so you will have some non-zero field on both sides over 2 still, as Griffith's puts it "Averaging is really just a device for removing the contribution of the patch itself."
Apr 29, 2019 at 10:31 history edited ohneVal CC BY-SA 4.0
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Apr 27, 2019 at 12:20 comment added Ján Lalinský The factor of 1/2 is there because we deal with a closed surface. Other shapes such as half-sphere could have different factors. I see no basis for taking average of the two fields in the general case.
Apr 27, 2019 at 12:01 comment added pasaba por aqui This answer could be the accepted one if it includes a proof that the energy necessary to contruct a charged shell (or charged wire or sphere, if easier) is finite.
Apr 27, 2019 at 11:51 comment added my2cts This does not answer the question. It address calculation on a discrete grid, where care must be taken to correctly account for singularities.
Apr 25, 2019 at 17:25 history answered ohneVal CC BY-SA 4.0