Skip to main content
added 1 character in body
Source Link
thunderbolt
  • 776
  • 4
  • 11

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{cL}$$\Delta E \geq \frac{\hbar c}{L}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Have a look at these lecture notes from where I have sourced this answer: http://www.damtp.cam.ac.uk/user/tong/qft/one.pdf

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{cL}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Have a look at these lecture notes from where I have sourced this answer: http://www.damtp.cam.ac.uk/user/tong/qft/one.pdf

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar c}{L}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Have a look at these lecture notes from where I have sourced this answer: http://www.damtp.cam.ac.uk/user/tong/qft/one.pdf

added 126 characters in body
Source Link
thunderbolt
  • 776
  • 4
  • 11

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{cL}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Have a look at these lecture notes from where I have sourced this answer: http://www.damtp.cam.ac.uk/user/tong/qft/one.pdf

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{cL}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{cL}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Have a look at these lecture notes from where I have sourced this answer: http://www.damtp.cam.ac.uk/user/tong/qft/one.pdf

deleted 4 characters in body
Source Link
thunderbolt
  • 776
  • 4
  • 11

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{\pi cL}$$\Delta E \geq \frac{\hbar}{cL}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{\pi cL}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Consider a particle of mass m confined in a box of length L, the uncertainty in the momentum is of the order $\Delta p \geq \frac{\hbar}{L} $. Relativistically, energy and momentum are on the same footing. So, uncertainty in the energy is of the order $\Delta E \geq \frac{\hbar}{cL}$. When the uncertainty in the energy exceeds $2mc^2$ ($ L = \frac{\hbar}{mc})$ it is possible to create particle anti-particle pairs from the vacuum.

Thus, there is a high probability that we will detect particle-antiparticle pairs swarming the original particle at length scales smaller than the Compton wavelength $\frac{\hbar}{mc}$. The notion of a single, localized particle breaks down completely below the Compton wavelength.

Source Link
thunderbolt
  • 776
  • 4
  • 11
Loading