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Apr 4, 2019 at 10:32 comment added Aleksey Druggist @M. Winter, in physics, the macrostate " in question " is the state in which system exists or more accurately spend most of the time, so we (or the system) must choose the macrostate with the highest stat. weight, that is, highest $ \Omega$. Analogy: the extremum of the function (entropy) is a property of the function (system) and not a particular function value of particular argument value
Apr 4, 2019 at 8:19 comment added M. Winter +1. "Entropy is a property of a macrostate, not a system." is completely clear, but I have never heard that before. It clarified my thinking a lot.
Apr 3, 2019 at 15:35 history edited Acccumulation CC BY-SA 4.0
making discussing of infinite microstates more explicit
Apr 3, 2019 at 15:31 comment added Acccumulation @Runlikehell I was trying to get at the infinity problem with my last paragraph, but I think I'll make that a bit more clear.
Apr 3, 2019 at 14:59 comment added RenatoRenatoRenato +1; You may add for completeness that $\Omega$ is actually the volume occupied by all the possible microstates corresponding to the given macrostate, in phase space. I Always found this expression clearer, since both positions and momentum are continuous variables, the number of microstates available would be infinite.
Apr 3, 2019 at 1:35 vote accept CommunityBot
Apr 3, 2019 at 1:22 history answered Acccumulation CC BY-SA 4.0