Timeline for How do I solve the current of this resistor using Maxwell's Current Theorem?
Current License: CC BY-SA 3.0
3 events
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| Dec 14, 2012 at 15:40 | comment | added | Muphrid | The third line you just wrote is not an equation. Setting up this equation tells you the current through the 20 ohm resistor (because you must find its expression in terms of the 3 loop currents to set up this equation). In addition, I think you have an inconsistent sign convention for your currents (this tends to be tricky). | |
| Dec 14, 2012 at 7:36 | comment | added | Christy McGrory | As far as I can tell the three loops are: $$ 1) 20=5I1 + 10(I1-I2) $$ $$ 2) 10 = 10(I1-I2) + 15(I2+I3) $$ $$ 3) 20I3 + 15(I2 + I3) $$ What I am really stuck on is finding out the value of the current at the 20ohm resistor. | |
| Dec 14, 2012 at 7:19 | history | answered | Muphrid | CC BY-SA 3.0 |