Timeline for Divergence of $ \frac{1}{s}\hat{s}$ in cylindrical coordinates
Current License: CC BY-SA 4.0
16 events
when toggle format | what | by | license | comment | |
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Mar 18, 2019 at 15:38 | vote | accept | ben tenyson | ||
Mar 18, 2019 at 15:28 | history | edited | ben tenyson | CC BY-SA 4.0 |
added 7 characters in body
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Mar 18, 2019 at 15:16 | answer | added | CR Drost | timeline score: 3 | |
Mar 18, 2019 at 14:57 | comment | added | ben tenyson | @Aaron Stevens I have added more details to my question now | |
Mar 18, 2019 at 14:56 | history | edited | ben tenyson | CC BY-SA 4.0 |
added 278 characters in body
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S Mar 18, 2019 at 14:50 | history | suggested | EisMC2 | CC BY-SA 4.0 |
Probably trivial, but improves the structure.
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Mar 18, 2019 at 14:48 | review | Suggested edits | |||
S Mar 18, 2019 at 14:50 | |||||
Mar 18, 2019 at 14:11 | comment | added | ben tenyson | @ Sourabh it is the radius in cylindrical coordinates | |
Mar 18, 2019 at 14:10 | review | Close votes | |||
Mar 21, 2019 at 15:36 | |||||
Mar 18, 2019 at 14:03 | history | edited | ben tenyson | CC BY-SA 4.0 |
added 340 characters in body
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Mar 18, 2019 at 13:59 | comment | added | ben tenyson | @Aaron Stevens so only way that's true is if it is $2\pi\delta(s)$ Is this correct? | |
Mar 18, 2019 at 13:58 | comment | added | reddot | What is s can you define | |
Mar 18, 2019 at 13:58 | comment | added | ben tenyson | When I put the vector field into the expression for divergence in polar coordinates I get 0 but if I take a cylindrical surface around it it gives me 2\pi but I am not sure about it Is this true? | |
Mar 18, 2019 at 13:55 | history | edited | BioPhysicist |
edited tags
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Mar 18, 2019 at 13:55 | review | First posts | |||
Mar 18, 2019 at 14:36 | |||||
Mar 18, 2019 at 13:51 | history | asked | ben tenyson | CC BY-SA 4.0 |