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Thomas Fritsch
Thomas Fritsch
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enter image description here

According to Wikipedia:Gaussian beam the beam waist ($w_0$) and the total angular spread of the beam ($\Theta$) are related by

$$ \pi w_0 \tan \frac \Theta 2 = \lambda $$

From this formula you see: The wave-nature of light (via its wavelength $\lambda$) is responsible for the non-zero waist.

That means you would have a beam waist $w_0 = 0$ only for these cases:

  • wavelength $\lambda = 0$ (so that there is no diffraction)
  • total angular spread $\Theta = 180°$ (meaning we have a spherical wave from a point source)

enter image description here

According to Wikipedia:Gaussian beam the beam waist ($w_0$) and the total angular spread of the beam ($\Theta$) are related by

$$ \pi w_0 \tan \frac \Theta 2 = \lambda $$

From this formula you see: The wave-nature of light (via its wavelength $\lambda$) is responsible for the non-zero waist.

That means you would have a beam waist $w_0 = 0$ only for these cases:

  • wavelength $\lambda = 0$ (so that there is no diffraction)
  • total angular spread $\Theta = 180°$ (meaning we have a spherical wave from point source)

enter image description here

According to Wikipedia:Gaussian beam the beam waist ($w_0$) and the total angular spread of the beam ($\Theta$) are related by

$$ \pi w_0 \tan \frac \Theta 2 = \lambda $$

From this formula you see: The wave-nature of light (via its wavelength $\lambda$) is responsible for the non-zero waist.

That means you would have a beam waist $w_0 = 0$ only for these cases:

  • wavelength $\lambda = 0$ (so that there is no diffraction)
  • total angular spread $\Theta = 180°$ (meaning we have a spherical wave from a point source)
more exact conclusion
Source Link
Thomas Fritsch
Thomas Fritsch
  • 41k
  • 13
  • 75
  • 144

enter image description here

According to Wikipedia:Gaussian beam the beam waist ($w_0$) and the total angular spread of the beam ($\Theta$) are related by

$$ \pi w_0 \tan \frac \Theta 2 = \lambda $$

From this formula you see: The wave-nature of light (via its wavelength $\lambda$) is responsible for the non-zero waist. Only with a wavelength $\lambda = 0$

That means you would have a beam waist $w_0 = 0$. only for these cases:

  • wavelength $\lambda = 0$ (so that there is no diffraction)
  • total angular spread $\Theta = 180°$ (meaning we have a spherical wave from point source)

enter image description here

According to Wikipedia:Gaussian beam the beam waist ($w_0$) and the total angular spread of the beam ($\Theta$) are related by

$$ \pi w_0 \tan \frac \Theta 2 = \lambda $$

From this formula you see: The wave-nature of light (via its wavelength $\lambda$) is responsible for the non-zero waist. Only with a wavelength $\lambda = 0$ you would have a beam waist $w_0 = 0$.

enter image description here

According to Wikipedia:Gaussian beam the beam waist ($w_0$) and the total angular spread of the beam ($\Theta$) are related by

$$ \pi w_0 \tan \frac \Theta 2 = \lambda $$

From this formula you see: The wave-nature of light (via its wavelength $\lambda$) is responsible for the non-zero waist.

That means you would have a beam waist $w_0 = 0$ only for these cases:

  • wavelength $\lambda = 0$ (so that there is no diffraction)
  • total angular spread $\Theta = 180°$ (meaning we have a spherical wave from point source)
Source Link
Thomas Fritsch
Thomas Fritsch
  • 41k
  • 13
  • 75
  • 144

enter image description here

According to Wikipedia:Gaussian beam the beam waist ($w_0$) and the total angular spread of the beam ($\Theta$) are related by

$$ \pi w_0 \tan \frac \Theta 2 = \lambda $$

From this formula you see: The wave-nature of light (via its wavelength $\lambda$) is responsible for the non-zero waist. Only with a wavelength $\lambda = 0$ you would have a beam waist $w_0 = 0$.